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(D) To balance the chemical equation for the aerobic respiration of a fat molecule (like tripalmitin), we use the law of conservation of mass.The gene

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$2(C_{51}H_{98} O_6), 98 H_2O$

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(D) To balance the chemical equation for the aerobic respiration of a fat molecule (like tripalmitin), we use the law of conservation of mass.The general equation is $2(C_{51}H_{98}O_6) + 145 O_2 ightarrow 102 CO_2 + 98 H_2O + 	ext{energy}$.$1$. Carbon atoms: $2 	imes 51 = 102$ on the reactant side, and $102$ on the product side.$2$. Hydrogen atoms: $2 	imes 98 = 196$ on the reactant side, and $98 	imes 2 = 196$ on the product side.$3$. Oxygen atoms: $(2 	imes 6) + (145 	imes 2) = 12 + 290 = 302$ on the reactant side, and $(102 	imes 2) + 98 = 204 + 98 = 302$ on the product side.Thus, the correct reactant is $2(C_{51}H_{98}O_6)$ and the water produced is $98 H_2O$.

$2 (C_{52} H_{89} O_{12}) + 145 O_2 \rightarrow 102 CO_2 + 89 H_2O + \text{energy}$.
To make the equation true, what should be placed in the reactant side instead of $2 (C_{52} H_{89} O_{12})$?

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$2 (C_{52} H_{89} O_{12}) + 145 O_2 \rightarrow 102 CO_2 + 89 H_2O + \text{energy}$.To make the equation true, what should be placed in the reactant side instead of $2 (C_{52} H_{89} O_{12})$?