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(D) The reaction is: $2BeCl_2 + LiAlH_4 	o 2BeH_2 + LiCl + AlCl_3$.Thus,the compound $(X)$ is $BeH_2$.In the monomer form,$BeH_2$ is a linear molecul

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(D) The reaction is: $2BeCl_2 + LiAlH_4 	o 2BeH_2 + LiCl + AlCl_3$.Thus,the compound $(X)$ is $BeH_2$.In the monomer form,$BeH_2$ is a linear molecule with $sp$ hybridization.It contains two $Be-H$ covalent bonds,which are $2c-2e^\Theta$ bonds.There are no $3c-4e^\Theta$ bonds in the monomeric $BeH_2$ molecule.Therefore,the total number of $3c-4e^\Theta$ bonds is $0$.

$BeCl_2 + LiAlH_4 \to X + LiCl + AlCl_3$
Total number of $3c-4e^\Theta$ bonds present in the monomer form of compound $(X)$ is:

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$BeCl_2 + LiAlH_4 \to X + LiCl + AlCl_3$Total number of $3c-4e^\Theta$ bonds present in the monomer form of compound $(X)$ is: