A 1000 g sample of NaOH contains 3 moles of | vedclass

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(C) The chemical formula of $NaOH$ is $NaOH$. One mole of $NaOH$ contains $1 \ mole$ of $O$ atoms.Given that the sample contains $3 \ moles$ of $O$ at

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$12$

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(C) The chemical formula of $NaOH$ is $NaOH$. One mole of $NaOH$ contains $1 \ mole$ of $O$ atoms.Given that the sample contains $3 \ moles$ of $O$ atoms,the amount of pure $NaOH$ is $3 \ moles$.The molar mass of $NaOH$ is $23 + 16 + 1 = 40 \ g/mol$.Mass of pure $NaOH = 3 \ mol 	imes 40 \ g/mol = 120 \ g$.Percentage purity = $\frac{	ext{Mass of pure } NaOH}{	ext{Total mass of sample}} 	imes 100$.Percentage purity = $\frac{120 \ g}{1000 \ g} 	imes 100 = 12 \%$.

$A$ $1000 \ g$ sample of $NaOH$ contains $3 \ moles$ of $O$ atoms. What is the $Purity$ of $NaOH$ $\dots \dots \dots \dots \dots \dots \%$

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