(A) The concentration of $H^{+}$ ions is given by $[H^{+}] = C \times \alpha$.Given $C = 0.1 \ N$ and $\alpha = 0.1$,we have $[H^{+}] = 0.1 \times 0.1

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(A) The concentration of $H^{+}$ ions is given by $[H^{+}] = C \times \alpha$.Given $C = 0.1 \ N$ and $\alpha = 0.1$,we have $[H^{+}] = 0.1 \times 0.1 = 10^{-2} \ M$.At room temperature,the ionic product of water is $K_w = [H^{+}][OH^{-}] = 10^{-14}$.Therefore,$[OH^{-}] = \frac{10^{-14}}{[H^{+}]} = \frac{10^{-14}}{10^{-2}} = 10^{-12} \ M$.

Class 11 Chemistry 6-2.Equilibrium-II (Ionic Equilibrium)Mix Examples-Ionic Equilibrium

Medium

$A$ $0.1 \ N$ solution of an acid at room temperature has a degree of ionisation $0.1$. The concentration of $OH^{-}$ would be

A
$10^{-12} \ M$
B
$10^{-11} \ M$
C
$10^{-9} \ M$
D
$10^{-2} \ M$

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6-2.Equilibrium-II (Ionic Equilibrium)

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Mix Examples-Ionic Equilibrium

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At $90 \, ^\circ C$,the concentration of $H^+$ and $OH^-$ ions in pure water is $10^{-6} \, M$. What is the value of $[H^+] + [OH^-]$ at this temperature?

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$A$ $0.1 \ N$ solution of an acid at room temperature has a degree of ionisation $0.1$. The concentration of $OH^{-}$ would be

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Arrange the following $1 \ L$ aqueous solutions of equal concentration in increasing order of their $pH$:$CH_3COONa, KI, NH_4Cl, HNO_3$

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Arrange the following $1 \ L$ aqueous solutions of equal concentration in increasing order of their $pH$:
$CH_3COONa, KI, NH_4Cl, HNO_3$