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(C) The relationship between linear momentum $P$,mass $m$,and kinetic energy $E$ is given by the formula $P = \sqrt{2mE}$.Since the kinetic energies $

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$2:1$

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(C) The relationship between linear momentum $P$,mass $m$,and kinetic energy $E$ is given by the formula $P = \sqrt{2mE}$.Since the kinetic energies $E$ are equal for both masses,we can write the ratio of their momenta as:$\frac{P_1}{P_2} = \frac{\sqrt{2m_1E}}{\sqrt{2m_2E}} = \sqrt{\frac{m_1}{m_2}}$.Given $m_1 = 4 \, kg$ and $m_2 = 1 \, kg$,we substitute these values into the equation:$\frac{P_1}{P_2} = \sqrt{\frac{4}{1}} = \sqrt{4} = 2$.Therefore,the ratio of the magnitudes of their linear momenta is $2:1$.

$A$ $4 \, kg$ mass and a $1 \, kg$ mass are moving with equal kinetic energies. The ratio of the magnitudes of their linear momenta is

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