A 5 % solution of cane sugar (mol. wt. = 342) | vedclass

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(C) Two solutions are isotonic if they have the same molar concentration (molarity).Molar concentration of cane sugar $= \frac{5 \ g}{342 \ g/mol} 	i

Vedclass · Accepted Answer

$68.4$

Vedclass · Answer

(C) Two solutions are isotonic if they have the same molar concentration (molarity).Molar concentration of cane sugar $= \frac{5 \ g}{342 \ g/mol} 	imes \frac{1000 \ mL}{100 \ mL} = \frac{50}{342} \ M$.Molar concentration of substance $X$ $= \frac{1 \ g}{m \ g/mol} 	imes \frac{1000 \ mL}{100 \ mL} = \frac{10}{m} \ M$.Since the solutions are isotonic,their molar concentrations are equal:$\frac{10}{m} = \frac{50}{342}$.Solving for $m$:$m = \frac{342 	imes 10}{50} = \frac{342}{5} = 68.4$.

$A$ $5 \%$ solution of cane sugar (mol. wt. $= 342$) is isotonic with $1 \%$ solution of a substance $X$. The molecular weight of $X$ is

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