$A$ $6\,\mu F$ capacitor is charged from $10\,V$ to $20\,V$. The increase in energy will be:

For a capacitor with area $A$ and potential difference $V$ separated by a distance $d$,the energy per unit volume is:

The energy of a parallel plate capacitor when connected to a battery is $E$. With the battery still in connection,if the plates of the capacitor are separated so that the distance between them is twice the original distance,then the electrostatic energy becomes

Work done in placing a charge of $8 \times 10^{-18} \text{ C}$ on a capacitor of capacitance $800 \mu\text{F}$ is . . . . . . .

The energy stored in a capacitor of capacity $C$ which has been raised to a potential $V$ is given by

The amount of work done in increasing the voltage across the plates of a capacitor from $5 \ V$ to $10 \ V$ is $W$. The work done in increasing it from $10 \ V$ to $15 \ V$ will be (nearly):