(B) The energy $U$ stored in a capacitor is given by the formula $U = \frac{1}{2} C V^2$.Given: $C = 40 \, \mu F = 40 \times 10^{-6} \, F$,$V = 3000 \

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(B) The energy $U$ stored in a capacitor is given by the formula $U = \frac{1}{2} C V^2$.Given: $C = 40 \, \mu F = 40 \times 10^{-6} \, F$,$V = 3000 \, V$,and $t = 2 \, ms = 2 \times 10^{-3} \, s$.First,calculate the energy stored:$U = \frac{1}{2} \times (40 \times 10^{-6}) \times (3000)^2$$U = 20 \times 10^{-6} \times 9 \times 10^6 = 180 \, J$.Power $P$ is defined as the energy delivered per unit time:$P = \frac{U}{t} = \frac{180 \, J}{2 \times 10^{-3} \, s} = 90 \times 10^3 \, W = 90 \, kW$.

Class 12 Physics Electric Potential and Capacitance Energy Stored in a Capacitor

Medium

$A$ $40 \, \mu F$ capacitor in a defibrillator is charged to $3000 \, V$. The energy stored in the capacitor is sent through the patient during a pulse of duration $2 \, ms$. The power delivered to the patient is ...... $kW$.

AIIMS 2004 All AIIMS

A
$45$
B
$90$
C
$180$
D
$360$

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Class 12

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Electric Potential and Capacitance

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Energy Stored in a Capacitor

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AIIMS 2004 Paper All AIIMS years →

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$A$ $40 \, \mu F$ capacitor in a defibrillator is charged to $3000 \, V$. The energy stored in the capacitor is sent through the patient during a pulse of duration $2 \, ms$. The power delivered to the patient is ...... $kW$.

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$A$ capacitor of capacity $50\,\mu F$ is charged to $10\;V$. Its energy is equal to:

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