The products A and B formed in the following | vedclass

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Question

(A) The reaction of chromyl chloride $(CrO_2Cl_2)$ with $NaOH$ produces sodium chromate $(Na_2CrO_4)$ as follows:$CrO_2Cl_2 + 4NaOH \rightarrow Na_2Cr

Vedclass · Accepted Answer

$A = Na_2CrO_4, B = CrO_5$

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(A) The reaction of chromyl chloride $(CrO_2Cl_2)$ with $NaOH$ produces sodium chromate $(Na_2CrO_4)$ as follows:$CrO_2Cl_2 + 4NaOH \rightarrow Na_2CrO_4 + 2NaCl + 2H_2O$Therefore,$A = Na_2CrO_4$.Sodium chromate reacts with hydrogen peroxide $(H_2O_2)$ in an acidic medium $(HCl)$ to form the deep blue colored chromium pentoxide $(CrO_5)$:$Na_2CrO_4 + 2HCl + 2H_2O_2 \rightarrow CrO_5 + 2NaCl + 3H_2O$Therefore,$B = CrO_5$.

The products $A$ and $B$ formed in the following reactions are:
$CrO_2Cl_2 + 4NaOH \rightarrow A + 2NaCl + 2H_2O$
$A + 2HCl + 2H_2O_2 \rightarrow B + 3H_2O$

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The products $A$ and $B$ formed in the following reactions are:$CrO_2Cl_2 + 4NaOH \rightarrow A + 2NaCl + 2H_2O$$A + 2HCl + 2H_2O_2 \rightarrow B + 3H_2O$