A bag contains 3 red,4 white and 5 blue balls | vedclass

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(A) Total number of balls $= 3 + 4 + 5 = 12$.Number of ways to draw $2$ balls from $12$ is ${}^{12}C_2 = \frac{12 	imes 11}{2} = 66$.To find the prob

Vedclass · Accepted Answer

$\frac{47}{66}$

Vedclass · Answer

(A) Total number of balls $= 3 + 4 + 5 = 12$.Number of ways to draw $2$ balls from $12$ is ${}^{12}C_2 = \frac{12 	imes 11}{2} = 66$.To find the probability that the balls are of different colours,it is easier to calculate the probability that they are of the same colour and subtract it from $1$.Number of ways to draw $2$ balls of the same colour:- Both red: ${}^{3}C_2 = 3$- Both white: ${}^{4}C_2 = 6$- Both blue: ${}^{5}C_2 = 10$Total ways for same colour $= 3 + 6 + 10 = 19$.Probability of same colour $= \frac{19}{66}$.Probability of different colours $= 1 - \frac{19}{66} = \frac{66 - 19}{66} = \frac{47}{66}$.

$A$ bag contains $3$ red,$4$ white and $5$ blue balls. All balls are different. Two balls are drawn at random. The probability that they are of different colour is

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