A ball is dropped from a height of 10 , m. If | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Initial potential energy of the ball at height $h = 10 \, m$ is $E = mgh$.After striking the ground,the energy reduces by $40 \%$,which means the

Vedclass · Accepted Answer

$6$

Vedclass · Answer

(B) Initial potential energy of the ball at height $h = 10 \, m$ is $E = mgh$.After striking the ground,the energy reduces by $40 \%$,which means the ball retains $60 \%$ of its initial energy.Energy retained $= 0.60 	imes mgh$.When the ball bounces back to a new height $h'$,its potential energy at that height will be $mgh'$.Equating the retained energy to the new potential energy: $mgh' = 0.60 	imes mgh$.Canceling $mg$ from both sides,we get $h' = 0.60 	imes h$.Substituting $h = 10 \, m$,we get $h' = 0.60 	imes 10 \, m = 6 \, m$.Therefore,the ball bounces back to a height of $6 \, m$.

$A$ ball is dropped from a height of $10 \, m$. If the energy of the ball reduces by $40 \%$ after striking the ground,how much high can the ball bounce back (in $, m$)? $(g = 10 \, m s^{-2})$

Similar Questions

We wind our watch once a day,what happens to the energy?

The work done by a force on a body will be positive if the:

Define work. Write an expression for work in terms of force and displacement. State the $SI$ unit of work done.

Define: $(a)$ power $(b)$ work done $(c)$ kinetic energy. Give the $SI$ unit of each.

$A$ rocket is moving up with a velocity $v$. If the velocity of this rocket is suddenly tripled,what will be the ratio of the initial kinetic energy to the final kinetic energy?

Vedclass Test Series

Exam Paper Generator

Online Exam Module