A ball is thrown vertically up (taken as +z- | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The momentum of the ball is given by $p = mv$,where $m$ is the mass and $v$ is the velocity.For motion under gravity,the relationship between velo

Vedclass · Accepted Answer

Vedclass · Answer

(A) The momentum of the ball is given by $p = mv$,where $m$ is the mass and $v$ is the velocity.For motion under gravity,the relationship between velocity $v$ and height $h$ is given by $v^2 = u^2 - 2gh$,where $u$ is the initial velocity.Substituting $v = p/m$ into the equation,we get $(p/m)^2 = u^2 - 2gh$.Rearranging this,we get $p^2 = m^2u^2 - 2gm^2h$,which can be written as $p^2 = -2gm^2h + m^2u^2$.This is the equation of a parabola of the form $p^2 = -Ah + B$,where $A = 2gm^2$ and $B = m^2u^2$.As the ball moves up,$p$ decreases from $mu$ to $0$ as $h$ increases from $0$ to $H_{max}$. As it falls back down,$p$ becomes negative and increases in magnitude from $0$ to $-mu$ as $h$ decreases from $H_{max}$ to $0$.The correct graph is a parabola opening towards the negative $h$-axis,starting at $p = mu$ (positive),passing through $p=0$ at $h=H_{max}$,and ending at $p = -mu$ (negative) at $h=0$.

$A$ ball is thrown vertically up (taken as $+z-$ axis) from the ground. The correct momentum-height $(p-h)$ diagram is

Similar Questions

$A$ ball is thrown vertically upwards from the ground $G$ with a speed $u$. It reaches a point $B$ at a height $h$ (lower than the maximum height) after time $t_1$. It returns to the ground after time $t_2$ from the instant it was at $B$ during the upward journey. Then $t_1t_2$ is equal to

$A$ stone is dropped from a certain height and reaches the ground in $5\, s$. If the stone is stopped after $3\, s$ of its fall and then allowed to fall again,then the time taken by the stone to reach the ground for the remaining distance is........$s$.

$A$ body thrown vertically up with initial velocity $52 \,m/s$ from the ground passes twice a point at $h$ height above at an interval of $10 \,s$. The height $h$ is .........$m$ $(g=10 \,m/s^2)$.

$A$ stone is thrown upwards with a velocity $50 \,ms^{-1}$. Another stone is simultaneously thrown downwards from the same location with a velocity $50 \,ms^{-1}$. When the first stone is at the highest point, the velocity of the second stone is $...... \,ms^{-1}$ (Take $g = 10 \,ms^{-2}$).

$A$ ball is thrown vertically upwards from the top of a tower at $4.9 \ m/s$. It strikes the pond near the base of the tower after $3 \ s$. The height of the tower is........$m$

Vedclass Test Series

Exam Paper Generator

Online Exam Module