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(D) Given:Initial velocity $u = 49\, m/s$Final velocity at maximum height $v = 0\, m/s$Acceleration due to gravity $g = -9.8\, m/s^2$ (acting downward

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$122.5\, m$,$10\, s$

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(D) Given:Initial velocity $u = 49\, m/s$Final velocity at maximum height $v = 0\, m/s$Acceleration due to gravity $g = -9.8\, m/s^2$ (acting downwards)$(i)$ To find the maximum height $(h)$:Using the third equation of motion: $v^2 - u^2 = 2gh$$0^2 - (49)^2 = 2 	imes (-9.8) 	imes h$$-2401 = -19.6 	imes h$$h = 2401 / 19.6 = 122.5\, m$$(ii)$ To find the total time of flight $(T)$:Using the first equation of motion for ascent: $v = u + gt$$0 = 49 + (-9.8) 	imes t$$9.8t = 49$$t = 5\, s$Since the time of ascent equals the time of descent,the total time $T = 2 	imes t = 2 	imes 5 = 10\, s$.

$A$ ball is thrown vertically upwards with a velocity of $49\, m/s$. Calculate
$(i)$ the maximum height to which it rises,
$(ii)$ the total time it takes to return to the surface of the earth.

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$A$ ball is thrown vertically upwards with a velocity of $49\, m/s$. Calculate$(i)$ the maximum height to which it rises,$(ii)$ the total time it takes to return to the surface of the earth.