A bandwidth of 6 , text{MHz} is available for | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The bandwidth required for a single $A.M.$ station is twice the maximum frequency of the modulating audio signal.$	ext{Bandwidth per station} = 2

Vedclass · Accepted Answer

$500$

Vedclass · Answer

(D) The bandwidth required for a single $A.M.$ station is twice the maximum frequency of the modulating audio signal.$	ext{Bandwidth per station} = 2 	imes f_m = 2 	imes 6 \, 	ext{kHz} = 12 \, 	ext{kHz}$.The total available bandwidth is $6 \, 	ext{MHz} = 6000 \, 	ext{kHz}$.The number of stations $N$ that can be broadcasted simultaneously is given by the ratio of the total bandwidth to the bandwidth per station:$N = \frac{	ext{Total Bandwidth}}{	ext{Bandwidth per station}} = \frac{6000 \, 	ext{kHz}}{12 \, 	ext{kHz}} = 500$.Therefore,$500$ stations can be broadcasted simultaneously.

Similar Questions

$A$ $TV$ tower has a height of $5 \, m$ in a region of population density $\frac{1000}{\pi}$ per square kilometre. The number of people that can receive the transmission is nearly, (in thousands)

In general,a transmitting antenna is........

The physical sizes of the transmitter and receiver antenna in a communication system are

In satellite communication,the uplink frequency band used is

If $f_m$ is the modulation frequency for $FM$,then the modulation index is proportional to.....

Vedclass Test Series

Exam Paper Generator

Online Exam Module