A bar magnet falls with its north pole pointi | vedclass

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(C) According to Lenz's law,the direction of the induced current is such that it opposes the change in magnetic flux that produced it.$1$. When the ma

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counter clockwise,while the magnet is above the plane of the ring and clockwise,while below the plane of the ring

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(C) According to Lenz's law,the direction of the induced current is such that it opposes the change in magnetic flux that produced it.$1$. When the magnet is above the ring and falling towards it,the magnetic flux through the ring increases. To oppose this,the ring develops a north pole on its upper face to repel the falling magnet. $A$ north pole corresponds to a counter-clockwise current when viewed from above.$2$. When the magnet passes through the ring and moves away below it,the magnetic flux through the ring decreases. To oppose this decrease,the ring develops a south pole on its lower face (which acts as a north pole on its upper face relative to the receding magnet) to attract the magnet. This corresponds to a clockwise current when viewed from above.Therefore,the current is counter-clockwise while the magnet is above the ring and clockwise while it is below the ring.

$A$ bar magnet falls with its north pole pointing down through the axis of a copper ring. When viewed from above,the current in the ring will be

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