A bar magnet is moved along the axis of a cop | vedclass

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(B) According to Lenz's law,the induced current in a loop opposes the change in magnetic flux that produces it.When viewed from the side of the magnet

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The north pole faces the ring and the magnet moves towards it.

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(B) According to Lenz's law,the induced current in a loop opposes the change in magnetic flux that produces it.When viewed from the side of the magnet,an anticlockwise current in the ring creates a magnetic field directed towards the magnet (acting as a North pole).If the North pole of the magnet faces the ring and moves towards it,the magnetic flux through the ring increases. To oppose this,the ring induces a North pole to repel the magnet.If the South pole of the magnet faces the ring and moves away from it,the magnetic flux through the ring decreases. To oppose this,the ring induces a North pole to attract the magnet.Therefore,both the North pole facing the ring and moving towards it,or the South pole facing the ring and moving away from it,would result in an anticlockwise current. Among the given options,$B$ is a correct possibility.

$A$ bar magnet is moved along the axis of a copper ring placed far away from the magnet. Looking from the side of the magnet,an anticlockwise current is found to be induced in the ring. Which of the following may be true?

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Assertion : Lenz's law violates the principle of conservation of energy.
Reason : Induced $emf$ always opposes the change in magnetic flux responsible for its production.

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