A beaker of radius 15, cm is filled with a li | vedclass

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(D) The force $F$ acting across an imaginary line of length $\ell$ on the surface of a liquid is given by $F = T 	imes \ell$,where $T$ is the surface

Vedclass · Accepted Answer

$2.25 	imes 10^{-2}\, N$

Vedclass · Answer

(D) The force $F$ acting across an imaginary line of length $\ell$ on the surface of a liquid is given by $F = T 	imes \ell$,where $T$ is the surface tension.For an imaginary diameter,the length $\ell$ is equal to the diameter of the beaker.Given,radius $r = 15\, cm = 0.15\, m$.Therefore,diameter $\ell = 2r = 2 	imes 0.15 = 0.30\, m$.Given surface tension $T = 0.075\, N/m$.Substituting the values into the formula:$F = 0.075 	imes 0.30$$F = 0.0225\, N$$F = 2.25 	imes 10^{-2}\, N$.

$A$ beaker of radius $15\, cm$ is filled with a liquid of surface tension $0.075\, N/m$. The force across an imaginary diameter on the surface of the liquid is:

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