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(D) When a beam of electrons passes undeflected through mutually perpendicular electric $(E)$ and magnetic $(B)$ fields, the net force on the electron

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in a circular orbit

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(D) When a beam of electrons passes undeflected through mutually perpendicular electric $(E)$ and magnetic $(B)$ fields, the net force on the electrons is zero. This implies that the electric force $(F_e = qE)$ is equal and opposite to the magnetic force $(F_m = qvB)$, so $qE = qvB$, or $v = E/B$.When the electric field is switched off, only the magnetic field remains. The magnetic force acting on a moving charge in a uniform magnetic field is given by $F = q(v 	imes B)$.Since the velocity vector $v$ is perpendicular to the magnetic field vector $B$, the magnetic force acts as a centripetal force, which is always perpendicular to the velocity of the electron.$A$ constant force acting perpendicular to the velocity of a particle results in circular motion. Therefore, the electrons will move in a circular orbit.

$A$ beam of electrons passes undeflected through mutually perpendicular electric and magnetic fields. If the electric field is switched off, and the same magnetic field is maintained, the electrons move

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