A bimetallic strip consists of metals X and Y | vedclass

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(B) bimetallic strip works on the principle of different coefficients of linear expansion $(\alpha)$ for different metals.Given that $\alpha_X > \alph

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It will bend towards the left

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(B) bimetallic strip works on the principle of different coefficients of linear expansion $(\alpha)$ for different metals.Given that $\alpha_X > \alpha_Y$.When the temperature decreases (placed in a cold bath), both metals contract.The change in length is given by $\Delta L = L_0 \alpha \Delta T$.Since $\alpha_X > \alpha_Y$, the metal $X$ will contract more than metal $Y$ for the same decrease in temperature $(\Delta T)$.Because metal $X$ is on the left and contracts more, it will pull the strip towards itself, causing the bimetallic strip to bend towards the left.

$A$ bimetallic strip consists of metals $X$ and $Y$. It is mounted rigidly at the base as shown in the figure. The metal $X$ has a higher coefficient of linear expansion compared to that of metal $Y$. When the bimetallic strip is placed in a cold bath, what happens?

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