A black body emits radiations of maximum inte | vedclass

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(B) According to Wien's displacement law,$\lambda_m T = 	ext{constant}$,so $\lambda_{m1} T_1 = \lambda_{m2} T_2$.Given: $\lambda_{m1} = 5000 \mathrin

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$3000$

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(B) According to Wien's displacement law,$\lambda_m T = 	ext{constant}$,so $\lambda_{m1} T_1 = \lambda_{m2} T_2$.Given: $\lambda_{m1} = 5000 \mathring A$,$T_1 = 1227 + 273 = 1500 \ K$.The temperature is increased by $1000^{\circ}C$,so the new temperature $T_2 = 1227 + 1000 + 273 = 2500 \ K$.Using the formula: $\lambda_{m2} = \frac{T_1}{T_2} 	imes \lambda_{m1}$.$\lambda_{m2} = \frac{1500}{2500} 	imes 5000 = 0.6 	imes 5000 = 3000 \mathring A$.

$A$ black body emits radiations of maximum intensity at a wavelength of $5000 \mathring A$,when the temperature of the body is $1227^{\circ}C$. If the temperature of the body is increased by $1000^{\circ}C$,the maximum intensity of emitted radiation would be observed at..... $\mathring A$.

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