A block of ice at -10^{circ} C is slowly heat | vedclass

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(C) The process of heating ice at $-10^{\circ} C$ to steam at $100^{\circ} C$ involves several stages:$1$. Heating ice from $-10^{\circ} C$ to $0^{\ci

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(C) The process of heating ice at $-10^{\circ} C$ to steam at $100^{\circ} C$ involves several stages:$1$. Heating ice from $-10^{\circ} C$ to $0^{\circ} C$: Temperature increases linearly with heat supplied.$2$. Melting ice at $0^{\circ} C$ to water at $0^{\circ} C$: Temperature remains constant (phase change,latent heat of fusion).$3$. Heating water from $0^{\circ} C$ to $100^{\circ} C$: Temperature increases linearly with heat supplied.$4$. Boiling water at $100^{\circ} C$ to steam at $100^{\circ} C$: Temperature remains constant (phase change,latent heat of vaporization).Thus,the heating curve should show two distinct horizontal segments representing the phase changes at $0^{\circ} C$ and $100^{\circ} C$,separated by a rising segment for water heating,and followed by a rising segment for steam heating. Graph $C$ correctly depicts these two phase changes (horizontal lines) and the intermediate heating stages.

$A$ block of ice at $-10^{\circ} C$ is slowly heated and converted to steam at $100^{\circ} C$. Which of the following curves represent the phenomenon qualitatively:

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