A block of mass m rests on a rough inclined p | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The forces acting on the block are the gravitational force $mg$ acting downwards,the normal reaction $N$ perpendicular to the plane,and the static

Vedclass · Accepted Answer

$	heta = 	an^{-1} \mu$

Vedclass · Answer

(A) The forces acting on the block are the gravitational force $mg$ acting downwards,the normal reaction $N$ perpendicular to the plane,and the static frictional force $f$ acting up the plane.When the block is about to slide,the component of weight down the plane must equal the maximum static friction.Equating the forces parallel to the plane: $mg \sin 	heta = f$ $...(i)$Equating the forces perpendicular to the plane: $mg \cos 	heta = N$ $...(ii)$Since the block is about to slide,the frictional force is at its maximum value,$f = \mu N$.Dividing equation $(i)$ by equation $(ii)$:$\frac{mg \sin 	heta}{mg \cos 	heta} = \frac{f}{N} = \frac{\mu N}{N}$$	an 	heta = \mu$Therefore,$	heta = 	an^{-1} (\mu)$.

$A$ block of mass $m$ rests on a rough inclined plane. The coefficient of friction between the surface and the block is $\mu$. At what angle of inclination $\theta$ of the plane to the horizontal will the block just start to slide down the plane?

Similar Questions

$A$ block of mass $1 \, kg$ is projected from the lowest point up along an inclined plane with an angle of inclination $45^{\circ}$ and coefficient of friction $\mu = 0.5$. If $g = 10 \, ms^{-2}$,the retardation experienced by the block is ............. $ms^{-2}$.

The force required just to move a body up an inclined plane is double the force required just to prevent the body from sliding down. If the coefficient of friction is $0.25$,the angle of inclination of the plane is ...... $^o$.

$A$ block of mass $5\,kg$ and surface area $2\,m^2$ just begins to slide down an inclined plane when the angle of inclination is $30^{\circ}$. Keeping the mass the same,the surface area of the block is doubled. The angle at which this starts sliding down is:

$A$ uniform chain of length $L$ hangs partly from a table and is kept in equilibrium by friction. If the maximum length that can hang without slipping is $\ell$,then the coefficient of friction between the table and the chain is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module