$A$ block of mass $100 \ kg$ slides over a distance of $10 \ m$ on a horizontal surface. If the coefficient of friction between the surfaces is $0.4$,then the work done against friction (in $J$) is:

$A$ heavy box is pushed across a rough floor with an initial speed of $4 \, m/s$. It stops moving after $8 \, s$. If the average resisting force of friction is $10 \, N$,the mass of the box (in $kg$) is:

If the normal reaction is $R$ and the coefficient of friction is $\mu$,what is the work done against friction in moving a body by a distance $d$ slowly?

$A$ block of mass $10 \, kg$ is placed on a rough horizontal surface having a coefficient of friction $\mu = 0.5$. If a horizontal force of $100 \, N$ is acting on it,then the acceleration of the block will be ....... $m/s^2$.

Explain kinetic friction. Write the laws of kinetic friction. Define the coefficient of kinetic friction.

$A$ block of mass $1.5 \ kg$ kept on a rough horizontal surface is given a horizontal velocity of $10 \ ms^{-1}$. If the block comes to rest after travelling a distance of $12.5 \ m$,the coefficient of kinetic friction between the surface and the block is (Acceleration due to gravity $= 10 \ ms^{-2}$)