(A) The apparent weight of an object submerged in a fluid is given by the formula: $W_{app} = W_{actual} - F_B$,where $F_B$ is the buoyant force.$W_{a

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(A) The apparent weight of an object submerged in a fluid is given by the formula: $W_{app} = W_{actual} - F_B$,where $F_B$ is the buoyant force.$W_{app} = V_b \rho_s g - V_b \rho_w g = V_b g (\rho_s - \rho_w)$.Given:Volume of the block $V_b = 5 \times 5 \times 5 \, cm^3 = 125 \, cm^3$.Relative density of steel $\text{RD}_s = \frac{\rho_s}{\rho_w} = 7$,so $\rho_s = 7 \, g/cm^3$ and $\rho_w = 1 \, g/cm^3$.Substituting the values:$W_{app} = (5 \times 5 \times 5) \times (7 - 1) \, g wt$$W_{app} = 6 \times 5 \times 5 \times 5 \, g wt$.Thus,the correct option is $A$.

Class 11 Physics Fluid Mechanics and Surface Tension Buoyancy, Archimedes' Principle and Laws of Floatation

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$A$ block of steel of size $5 \times 5 \times 5 \, cm^3$ is weighed in water. If the relative density of steel is $7$,its apparent weight is ........... $g wt$.

A
$6 \times 5 \times 5 \times 5$
B
$4 \times 4 \times 4 \times 7$
C
$5 \times 5 \times 5 \times 7$
D
$4 \times 4 \times 4 \times 6$

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Fluid Mechanics and Surface Tension

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Buoyancy, Archimedes' Principle and Laws of Floatation

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$A$ block of steel of size $5 \times 5 \times 5 \, cm^3$ is weighed in water. If the relative density of steel is $7$,its apparent weight is ........... $g wt$.

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An ice cube contains a large air bubble. The cube is floating on the horizontal surface of water contained in a trough. What will happen to the water level when the cube melts?

$A$ ball rises to the surface at a constant velocity in a liquid whose density is $3$ times greater than that of the material of the ball. The ratio of the force of friction acting on the rising ball to its weight is (in $: 1$)

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