A boatman takes twice as long to row a distan | vedclass

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(B) Let the speed of the boat in still water be $x$ and the speed of the stream be $y$.Let the distance be $d$.The speed of the boat with the stream (

Vedclass · Accepted Answer

$3:1$

Vedclass · Answer

(B) Let the speed of the boat in still water be $x$ and the speed of the stream be $y$.Let the distance be $d$.The speed of the boat with the stream (downstream) is $(x + y)$ and against the stream (upstream) is $(x - y)$.According to the problem,the time taken to row upstream is twice the time taken to row downstream:$\frac{d}{x - y} = 2 	imes \frac{d}{x + y}$Canceling $d$ from both sides,we get:$\frac{1}{x - y} = \frac{2}{x + y}$$x + y = 2(x - y)$$x + y = 2x - 2y$Rearranging the terms,we get:$x = 3y$Therefore,the ratio of the speed of the boat in still water to the speed of the stream is $\frac{x}{y} = \frac{3}{1}$,which is $3:1$.

$A$ boatman takes twice as long to row a distance against the stream as to row the same distance with the stream. Find the ratio of the speed of the boat in still water to the speed of the stream.

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