A body falling from a height of 10,m rebounds | vedclass

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Question

(A) Let the initial height be $h_1 = 10\,m$ and the rebound height be $h_2$.The initial potential energy is $PE_1 = mgh_1$.Since the body loses $20\%$

Vedclass · Accepted Answer

$0.89$

Vedclass · Answer

(A) Let the initial height be $h_1 = 10\,m$ and the rebound height be $h_2$.The initial potential energy is $PE_1 = mgh_1$.Since the body loses $20\%$ of its energy on impact,the remaining energy is $80\%$ of the initial energy.Thus,$mgh_2 = 0.80 	imes mgh_1$.This simplifies to $\frac{h_2}{h_1} = 0.8$.The coefficient of restitution $e$ is defined as the square root of the ratio of the rebound height to the initial height: $e = \sqrt{\frac{h_2}{h_1}}$.Substituting the value,$e = \sqrt{0.8} \approx 0.894$.Therefore,the coefficient of restitution is approximately $0.89$.

$A$ body falling from a height of $10\,m$ rebounds from a hard floor. If it loses $20\%$ of its energy on impact,then the coefficient of restitution is:

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