A body having a specific charge of 8,mu text{ | vedclass

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(B) The specific charge is given by $\frac{q}{m} = 8\,\mu 	ext{C/g} = 8 	imes 10^{-6} 	ext{ C} / 10^{-3} 	ext{ kg} = 8 	imes 10^{-3} 	ext{ C/kg}

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(B) The specific charge is given by $\frac{q}{m} = 8\,\mu 	ext{C/g} = 8 	imes 10^{-6} 	ext{ C} / 10^{-3} 	ext{ kg} = 8 	imes 10^{-3} 	ext{ C/kg}$.The force on the body due to the electric field is $F = qE$.The acceleration of the body is $a = \frac{F}{m} = \frac{qE}{m} = \left(\frac{q}{m}ight)E$.Substituting the values: $a = (8 	imes 10^{-3} 	ext{ C/kg}) 	imes (100 	ext{ V/m}) = 0.8 	ext{ m/s}^2$.The time taken to travel the distance $d = 10\,	ext{cm} = 0.1\,	ext{m}$ is $t = \sqrt{\frac{2d}{a}}$.$t = \sqrt{\frac{2 	imes 0.1}{0.8}} = \sqrt{\frac{0.2}{0.8}} = \sqrt{0.25} = 0.5\,	ext{s}$.Since the collision is perfectly elastic,the body will rebound with the same speed and return to its original position in another $0.5\,	ext{s}$.Therefore,the total time period of the motion is $T = 2t = 2 	imes 0.5 = 1.0\,	ext{s}$.

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