$A$ body is thrown vertically upwards. Its velocity goes on decreasing. What is the change in kinetic energy when its velocity becomes zero?
(N/A) The kinetic energy $(KE)$ of a body is given by the formula $KE = \frac{1}{2}mv^2$.
As the body is thrown vertically upwards,its velocity $(v)$ decreases due to the gravitational force acting downwards.
At the highest point,the velocity of the body becomes zero $(v = 0)$.
Consequently,the kinetic energy at the highest point becomes $KE = \frac{1}{2}m(0)^2 = 0$.
Therefore,the change in kinetic energy is equal to the initial kinetic energy $(KE_{initial} - 0 = KE_{initial})$,which is entirely converted into potential energy at that point.
As the body is thrown vertically upwards,its velocity $(v)$ decreases due to the gravitational force acting downwards.
At the highest point,the velocity of the body becomes zero $(v = 0)$.
Consequently,the kinetic energy at the highest point becomes $KE = \frac{1}{2}m(0)^2 = 0$.
Therefore,the change in kinetic energy is equal to the initial kinetic energy $(KE_{initial} - 0 = KE_{initial})$,which is entirely converted into potential energy at that point.
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