A body of mass 3,kg is acted on by a force wh | vedclass

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(D) The impulse applied to a body is equal to the change in its momentum. According to the impulse-momentum theorem,the impulse is equal to the area u

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$50$

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(D) The impulse applied to a body is equal to the change in its momentum. According to the impulse-momentum theorem,the impulse is equal to the area under the force-time $(F-t)$ graph.Impulse = Area under the $F-t$ graphThe graph consists of a triangle from $t = 0$ to $t = 2\,s$ and a rectangle from $t = 2\,s$ to $t = 6\,s$.Area of triangle = $\frac{1}{2} 	imes 	ext{base} 	imes 	ext{height} = \frac{1}{2} 	imes 2\,s 	imes 10\,N = 10\,N-s$.Area of rectangle = $	ext{length} 	imes 	ext{width} = (6 - 2)\,s 	imes 10\,N = 4\,s 	imes 10\,N = 40\,N-s$.Total momentum acquired = Total area = $10\,N-s + 40\,N-s = 50\,N-s$.Therefore,the correct option is $D$.

$A$ body of mass $3\,kg$ is acted on by a force which varies as shown in the graph below. The momentum acquired is given by ........... $N-s$.

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