(B) The initial kinetic energy $(K_i)$ is $490\, J$. At the height $h$ where the kinetic energy becomes half of its original value,the kinetic energy

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(B) The initial kinetic energy $(K_i)$ is $490\, J$. At the height $h$ where the kinetic energy becomes half of its original value,the kinetic energy $(K_f)$ is $\frac{490}{2} = 245\, J$. According to the law of conservation of energy,the loss in kinetic energy is equal to the gain in potential energy $(U)$. Loss in $K.E. = K_i - K_f = 490 - 245 = 245\, J$. Gain in potential energy $U = mgh$. Equating the two: $mgh = 245$. Substituting the given values: $2 \times 9.8 \times h = 245$. $19.6 \times h = 245$. $h = \frac{245}{19.6} = 12.5\, m$.

Class 11 Physics Work, Energy, Power and Collision Work Energy Theorem and Conservation of Mechanical Energy

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$A$ body of mass $2\, kg$ is thrown up vertically with a kinetic energy of $490\, J$. If the acceleration due to gravity is $9.8\, m/s^2$,then the height at which the kinetic energy of the body becomes half its original value is ............ $m$.

A
$50$
B
$12.5$
C
$25$
D
$10$

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Work, Energy, Power and Collision

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Work Energy Theorem and Conservation of Mechanical Energy

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$A$ body of mass $2\, kg$ is thrown up vertically with a kinetic energy of $490\, J$. If the acceleration due to gravity is $9.8\, m/s^2$,then the height at which the kinetic energy of the body becomes half its original value is ............ $m$.

Similar Questions

$A$ force of $5\,N$,making an angle $\theta$ with the horizontal,acts on an object and displaces it by $0.4\,m$ along the horizontal direction. If the object gains a kinetic energy of $1\,J$,the horizontal component of the force is......$N$. (in $.5$)

$A$ uniform chain of length $3\, m$ and mass $3\, kg$ overhangs a smooth table with $2\, m$ laying on the table. If $k$ is the kinetic energy of the chain in joules as it completely slips off the table,then the value of $k$ is (Take $g = 10\, m/s^2$).

The mass of a pendulum bob is $50 \ gm$. The bob is released from a horizontal position $A$ as shown in the figure. If the length of the pendulum is $1.5 \ m$,what will be its kinetic energy when it reaches the lowest point $B$ of its path? (Take $g = 10 \ m/s^2$)

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