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(A) The formula for kinetic energy is $K = \frac{1}{2}mv^2$.First,calculate the mean value of kinetic energy:$K = \frac{1}{2} 	imes 5 	imes (20)^2 =

Vedclass · Accepted Answer

$(1000 \pm 140) \ J$

Vedclass · Answer

(A) The formula for kinetic energy is $K = \frac{1}{2}mv^2$.First,calculate the mean value of kinetic energy:$K = \frac{1}{2} 	imes 5 	imes (20)^2 = \frac{1}{2} 	imes 5 	imes 400 = 1000 \ J$.Next,calculate the relative error using the formula for propagation of errors:$\frac{\Delta K}{K} = \frac{\Delta m}{m} + 2 \frac{\Delta v}{v}$.Substitute the given values:$\frac{\Delta K}{1000} = \frac{0.5}{5} + 2 	imes \frac{0.4}{20} = 0.1 + 0.04 = 0.14$.Calculate the absolute error $\Delta K$:$\Delta K = 1000 	imes 0.14 = 140 \ J$.Therefore,the kinetic energy is $(1000 \pm 140) \ J$.

$A$ body of mass $(5 \pm 0.5) \ kg$ is moving with a velocity of $(20 \pm 0.4) \ m/s$. Its kinetic energy will be

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