A body of weight 64, N is pushed with just en | vedclass

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(D) Given: Weight of the body $W = 64\, N$. Since $W = mg$,the mass $m = \frac{64}{g}$.The force required to start the motion is equal to the limiting

Vedclass · Accepted Answer

$0.2\, g$

Vedclass · Answer

(D) Given: Weight of the body $W = 64\, N$. Since $W = mg$,the mass $m = \frac{64}{g}$.The force required to start the motion is equal to the limiting static friction: $F = f_s = \mu_s N = \mu_s mg = 0.6 	imes 64 = 38.4\, N$.Once the body starts moving,the same force $F$ continues to act,but the friction force becomes kinetic friction: $f_k = \mu_k N = \mu_k mg = 0.4 	imes 64 = 25.6\, N$.The net force acting on the body is $F_{net} = F - f_k = 38.4 - 25.6 = 12.8\, N$.Using Newton's second law,$F_{net} = ma$,the acceleration $a = \frac{F_{net}}{m} = \frac{12.8}{64/g} = \frac{12.8}{64} g = 0.2\, g$.

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