A bomb of 12 , kg explodes into two pieces of | vedclass

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(D) Initially,the bomb is at rest,so the total initial momentum is $0$.According to the law of conservation of linear momentum,the total final momentu

Vedclass · Accepted Answer

$288$

Vedclass · Answer

(D) Initially,the bomb is at rest,so the total initial momentum is $0$.According to the law of conservation of linear momentum,the total final momentum must also be $0$.Let $v$ be the velocity of the $4 \, kg$ mass.$m_1 v_1 + m_2 v_2 = 0$$4 	imes v + 8 	imes 6 = 0$$4v = -48$$v = -12 \, m/s$ (The negative sign indicates the direction is opposite to the $8 \, kg$ mass).The magnitude of the velocity is $12 \, m/s$.The kinetic energy of the $4 \, kg$ mass is given by $KE = \frac{1}{2} m v^2$.$KE = \frac{1}{2} 	imes 4 	imes (12)^2$$KE = 2 	imes 144 = 288 \, J$.

$A$ bomb of $12 \, kg$ explodes into two pieces of masses $4 \, kg$ and $8 \, kg$. The velocity of $8 \, kg$ mass is $6 \, m/s$. The kinetic energy of the other mass is .............. $J$

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