A bomb of mass 10, kg explodes into two piece | vedclass

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Question

(A) Let the masses be $m_1 = 4\, kg$ and $m_2 = 6\, kg$. The kinetic energy of the first piece is $KE_1 = 200\, J$.The momentum of the first piece is

Vedclass · Accepted Answer

$\frac{400}{3}\,J$

Vedclass · Answer

(A) Let the masses be $m_1 = 4\, kg$ and $m_2 = 6\, kg$. The kinetic energy of the first piece is $KE_1 = 200\, J$.The momentum of the first piece is $p_1 = \sqrt{2 m_1 KE_1} = \sqrt{2 	imes 4 	imes 200} = \sqrt{1600} = 40\, kg\cdot m/s$.Since the bomb was initially at rest,the total momentum is zero. Therefore,the magnitudes of the momenta of the two pieces must be equal: $p_2 = p_1 = 40\, kg\cdot m/s$.The kinetic energy of the second piece is $KE_2 = \frac{p_2^2}{2 m_2} = \frac{40^2}{2 	imes 6} = \frac{1600}{12} = \frac{400}{3}\, J$.

$A$ bomb of mass $10\, kg$ explodes into two pieces of masses $4\, kg$ and $6\, kg$. If the kinetic energy of the $4\, kg$ piece is $200\, J$,find the kinetic energy of the $6\, kg$ piece.

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