A box contains 2 black,4 white,and 3 red ball | vedclass

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Question

(A) Total number of balls = $2 + 4 + 3 = 9$.We need to find the probability of drawing the balls in the specific sequence: $B, B, W, W, W, W, R, R, R$

Vedclass · Accepted Answer

$\frac{1}{1260}$

Vedclass · Answer

(A) Total number of balls = $2 + 4 + 3 = 9$.We need to find the probability of drawing the balls in the specific sequence: $B, B, W, W, W, W, R, R, R$.The probability is calculated as follows:$P = P(B_1) 	imes P(B_2|B_1) 	imes P(W_1|B_1, B_2) 	imes P(W_2|B_1, B_2, W_1) 	imes P(W_3|B_1, B_2, W_1, W_2) 	imes P(W_4|B_1, B_2, W_1, W_2, W_3) 	imes P(R_1|B_1, B_2, W_1, W_2, W_3, W_4) 	imes P(R_2|...) 	imes P(R_3|...)$$P = \frac{2}{9} 	imes \frac{1}{8} 	imes \frac{4}{7} 	imes \frac{3}{6} 	imes \frac{2}{5} 	imes \frac{1}{4} 	imes \frac{3}{3} 	imes \frac{2}{2} 	imes \frac{1}{1}$$P = \frac{2 	imes 1 	imes 4 	imes 3 	imes 2 	imes 1 	imes 3 	imes 2 	imes 1}{9 	imes 8 	imes 7 	imes 6 	imes 5 	imes 4 	imes 3 	imes 2 	imes 1} = \frac{288}{362880} = \frac{1}{1260}$.

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