A box contains 6 black and 4 red balls. Three | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Total number of balls = $6 + 4 = 10$.Number of ways to draw $3$ balls from $10$ balls is given by ${}^{10}C_3 = \frac{10 	imes 9 	imes 8}{3 	im

Vedclass · Accepted Answer

$1/2$

Vedclass · Answer

(A) Total number of balls = $6 + 4 = 10$.Number of ways to draw $3$ balls from $10$ balls is given by ${}^{10}C_3 = \frac{10 	imes 9 	imes 8}{3 	imes 2 	imes 1} = 120$.Number of ways to select $1$ red ball from $4$ red balls is ${}^{4}C_1 = 4$.Number of ways to select $2$ black balls from $6$ black balls is ${}^{6}C_2 = \frac{6 	imes 5}{2 	imes 1} = 15$.Number of favourable outcomes = ${}^{4}C_1 	imes {}^{6}C_2 = 4 	imes 15 = 60$.Probability $P(E) = \frac{	ext{Favourable outcomes}}{	ext{Total outcomes}} = \frac{60}{120} = \frac{1}{2}$.

$A$ box contains $6$ black and $4$ red balls. Three balls are drawn at random. What is the probability that one ball is red and the other two are black?

Similar Questions

$A$ number is chosen at random from the first ten natural numbers. The probability that the number is odd and a perfect square is

Four boys and three girls stand in a queue for an interview. What is the probability that they will stand in alternate positions?

From a well-shuffled pack of $52$ cards,one card is drawn at random. The probability that the card drawn is an ace is

$2$ dice are thrown. Find the odds against getting the sum $6$.

The probability of hitting a target by three marksmen are $\frac{1}{2}, \frac{1}{3}$ and $\frac{1}{4}$ respectively. The probability that one and only one of them will hit the target when they fire simultaneously,is

Vedclass Test Series

Exam Paper Generator

Online Exam Module