A box contains 5 red marbles,8 white marbles | vedclass

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(A) Total number of marbles $= 5 + 8 + 4 = 17$.$(i)$ Number of red marbles $= 5$.Probability of getting a red marble $= \frac{	ext{Number of favourab

Vedclass · Accepted Answer

$\frac{5}{17}, \frac{8}{17}, \frac{13}{17}$

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(A) Total number of marbles $= 5 + 8 + 4 = 17$.$(i)$ Number of red marbles $= 5$.Probability of getting a red marble $= \frac{	ext{Number of favourable outcomes}}{	ext{Number of total possible outcomes}} = \frac{5}{17}$.$(ii)$ Number of white marbles $= 8$.Probability of getting a white marble $= \frac{	ext{Number of favourable outcomes}}{	ext{Number of total possible outcomes}} = \frac{8}{17}$.$(iii)$ Number of green marbles $= 4$.Probability of getting a green marble $= \frac{4}{17}$.Probability of not getting a green marble $= 1 - P(	ext{green}) = 1 - \frac{4}{17} = \frac{13}{17}$.

$A$ box contains $5$ red marbles,$8$ white marbles and $4$ green marbles. One marble is taken out of the box at random. What is the probability that the marble taken out will be
$(i)$ red?
$(ii)$ white?
$(iii)$ not green?

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$A$ box contains $5$ red marbles,$8$ white marbles and $4$ green marbles. One marble is taken out of the box at random. What is the probability that the marble taken out will be$(i)$ red?$(ii)$ white?$(iii)$ not green?