A boy rides his bicycle 10 , km at an average | vedclass

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(B) Average speed $= \frac{	ext{Total distance travelled}}{	ext{Total time taken}}$Total distance travelled $= 10 \, km + 12 \, km = 22 \, km$Time t

Vedclass · Accepted Answer

$10.8$

Vedclass · Answer

(B) Average speed $= \frac{	ext{Total distance travelled}}{	ext{Total time taken}}$Total distance travelled $= 10 \, km + 12 \, km = 22 \, km$Time taken for the first part $= \frac{10 \, km}{12 \, km/hr} = \frac{5}{6} \, hr$Time taken for the second part $= \frac{12 \, km}{10 \, km/hr} = \frac{6}{5} \, hr$Total time taken $= \frac{5}{6} + \frac{6}{5} = \frac{25 + 36}{30} = \frac{61}{30} \, hr$Average Speed $= \frac{22}{\frac{61}{30}} = \frac{22 	imes 30}{61} = \frac{660}{61} \approx 10.82 \, km/hr$Thus,the average speed is approximately $10.8 \, km/hr$.

$A$ boy rides his bicycle $10 \, km$ at an average speed of $12 \, km/hr$ and again travels $12 \, km$ at an average speed of $10 \, km/hr$. His average speed for the entire trip is approximately (in $km/hr$)

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