(A) By the law of conservation of linear momentum,the initial momentum of the system equals the final momentum of the system.$mv + M(0) = (m + M)V$Whe

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

$\frac{1}{2}mv^2 \times \frac{m}{m+M}$

(A) By the law of conservation of linear momentum,the initial momentum of the system equals the final momentum of the system.$mv + M(0) = (m + M)V$Where $V$ is the velocity of the composite block after the collision.$V = \frac{mv}{m + M}$The kinetic energy $(KE)$ of the composite block is given by $KE = \frac{1}{2}(m + M)V^2$.Substituting the value of $V$:$KE = \frac{1}{2}(m + M) \left( \frac{mv}{m + M} \right)^2$$KE = \frac{1}{2}(m + M) \frac{m^2 v^2}{(m + M)^2}$$KE = \frac{1}{2} m v^2 \left( \frac{m}{m + M} \right)$

Class 11 Physics Work, Energy, Power and Collision Perfectly Inelastic Collision

Medium

$A$ bullet of mass $m$ moving with velocity $v$ strikes a block of mass $M$ at rest and gets embedded into it. The kinetic energy of the composite block will be

A
$\frac{1}{2}mv^2 \times \frac{m}{m+M}$
B
$\frac{1}{2}mv^2 \times \frac{M}{m+M}$
C
$\frac{1}{2}mv^2 \times \frac{M+m}{M}$
D
$\frac{1}{2}Mv^2 \times \frac{m}{m+M}$

Explore More

Browse All

Question Bank

All Subjects

Class 11 Questions

Class 11

Physics Questions

Chapter

Work, Energy, Power and Collision

Subtopic

Perfectly Inelastic Collision

$A$ block of mass $0.50 \ kg$ is moving with a speed of $2.00 \ m/s$ on a smooth surface. It strikes another mass of $1.00 \ kg$ at rest and then they move together as a single body. The energy loss during the collision is ............. $J$.

MediumAIEEE 2008

View Solution

$A$ neutron of mass $1.67 \times 10^{-27} \ kg$ moving with a velocity of $10^8 \ m/s$ collides with a deuteron at rest and sticks to it. If the mass of the deuteron is $3.34 \times 10^{-27} \ kg$,what will be the velocity of the combined system?

Difficult

View Solution

$A$ bullet of mass $m$ strikes a block of mass $M$ connected to a light spring of stiffness $k$,with a speed $V_0$. If the bullet gets embedded in the block,then the maximum compression in the spring is

View Solution

$A$ particle of mass $m$ moving with velocity $v$ collides with a stationary particle of mass $2m$. After collision,they stick together and continue to move together with velocity ........

MediumAIIMS 1999

View Solution

$A$ body of mass $2 \, kg$ moving with a velocity $(\hat{i} + \hat{j} + \hat{k}) \, m/s$ collides with another body of mass $5 \, kg$ moving with velocity $(\hat{i} - 2\hat{j} + 3\hat{k}) \, m/s$. If they stick together,the velocity (in $m/s$) of the composite body is:

Medium

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

$A$ bullet of mass $m$ moving with velocity $v$ strikes a block of mass $M$ at rest and gets embedded into it. The kinetic energy of the composite block will be

Similar Questions

$A$ block of mass $0.50 \ kg$ is moving with a speed of $2.00 \ m/s$ on a smooth surface. It strikes another mass of $1.00 \ kg$ at rest and then they move together as a single body. The energy loss during the collision is ............. $J$.

$A$ neutron of mass $1.67 \times 10^{-27} \ kg$ moving with a velocity of $10^8 \ m/s$ collides with a deuteron at rest and sticks to it. If the mass of the deuteron is $3.34 \times 10^{-27} \ kg$,what will be the velocity of the combined system?

$A$ bullet of mass $m$ strikes a block of mass $M$ connected to a light spring of stiffness $k$,with a speed $V_0$. If the bullet gets embedded in the block,then the maximum compression in the spring is

$A$ particle of mass $m$ moving with velocity $v$ collides with a stationary particle of mass $2m$. After collision,they stick together and continue to move together with velocity ........

$A$ body of mass $2 \, kg$ moving with a velocity $(\hat{i} + \hat{j} + \hat{k}) \, m/s$ collides with another body of mass $5 \, kg$ moving with velocity $(\hat{i} - 2\hat{j} + 3\hat{k}) \, m/s$. If they stick together,the velocity (in $m/s$) of the composite body is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module