A bullet of mass 10 ,g moving with a speed of | vedclass

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(C) $1$. Calculate the initial kinetic energy of the bullet: $KE_i = \frac{1}{2} m v^2 = \frac{1}{2} 	imes 0.01 \,kg 	imes (20 \,m/s)^2 = 2 \,J$.$2$

Vedclass · Accepted Answer

$0.003$

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(C) $1$. Calculate the initial kinetic energy of the bullet: $KE_i = \frac{1}{2} m v^2 = \frac{1}{2} 	imes 0.01 \,kg 	imes (20 \,m/s)^2 = 2 \,J$.$2$. Calculate the final velocity of the system (bullet + ice) using conservation of momentum: $m_b v_b = (m_b + m_i) v_f \Rightarrow 0.01 	imes 20 = (0.01 + 0.99) v_f \Rightarrow v_f = 0.2 \,m/s$.$3$. Calculate the final kinetic energy of the system: $KE_f = \frac{1}{2} (m_b + m_i) v_f^2 = \frac{1}{2} 	imes 1 \,kg 	imes (0.2 \,m/s)^2 = 0.02 \,J$.$4$. Calculate the lost kinetic energy: $\Delta KE = KE_i - KE_f = 2 - 0.02 = 1.98 \,J$.$5$. Energy available for melting ice: $Q = 50\% 	ext{ of } \Delta KE = 0.5 	imes 1.98 = 0.99 \,J \approx 1 \,J$.$6$. Amount of ice melted: $m_{melt} = \frac{Q}{L} = \frac{1 \,J}{336 \,J/g} \approx 0.00297 \,g \approx 0.003 \,g$.

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