$A$ bullet of mass $50 \ g$ is fired with a speed $100 \ m/s$ on a plywood and emerges with $40 \ m/s$. The percentage loss of kinetic energy is:

If the momentum of an object is doubled,what is the percentage increase in its kinetic energy (in $\%$)?

$A$ body of mass $m$ moving with velocity $v$ has kinetic energy equal to $\frac{1}{2} mv^2$. This statement is valid when:

$A$ body initially at rest is acted upon by a constant force $F$ for time $t$. The kinetic energy at time $t$ is

$A$ particle is released freely from a height $H$. At a certain height,its kinetic energy is two times its potential energy. Then,the height and the speed of the particle at that instant are respectively ($g=$ acceleration due to gravity).

An object has momentum $p$ and kinetic energy $E$. If its momentum becomes $2p$,then its kinetic energy will be: