A can complete a work in 10 days,B can comple | vedclass

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(B) 's work for the first day $= 1/10$.$B$'s work for the second day $= 1/20$.$C$'s work for the third day $= 1/40$.Work done in $3$ days by them $= 1

Vedclass · Accepted Answer

$16.5$

Vedclass · Answer

(B) 's work for the first day $= 1/10$.$B$'s work for the second day $= 1/20$.$C$'s work for the third day $= 1/40$.Work done in $3$ days by them $= 1/10 + 1/20 + 1/40 = (4+2+1)/40 = 7/40$.Hence,$7/40$ part of the work is completed in $3$ days.In $15$ days ($5$ cycles of $3$ days),the work completed $= 5 	imes (7/40) = 35/40 = 7/8$.Remaining work $= 1 - 7/8 = 1/8$.On the $16^{th}$ day,$A$ works. $A$ completes $1/10$ of the work.Remaining work after $16$ days $= 1/8 - 1/10 = (5-4)/40 = 1/40$.On the $17^{th}$ day,$B$ works. $B$ completes $1/20$ of the work in $1$ day.Time taken by $B$ to complete $1/40$ of the work $= 20 	imes (1/40) = 1/2$ day.Total time $= 15 + 1 + 1/2 = 16.5$ days.

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