A candle flame of 3 , cm is placed at 300 , c | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The height of the object is $h_o = 3 \, cm$ and the height of the real image formed on the wall is $h_i = -9 \, cm$ (since it is inverted).Magnifi

Vedclass · Accepted Answer

$450$

Vedclass · Answer

(C) The height of the object is $h_o = 3 \, cm$ and the height of the real image formed on the wall is $h_i = -9 \, cm$ (since it is inverted).Magnification $m = \frac{h_i}{h_o} = \frac{-9}{3} = -3$.We know that $m = -\frac{v}{u}$,so $-3 = -\frac{v}{u} \implies v = 3u$.From the geometry of the setup,the distance of the image from the mirror is $v = x$,and the distance of the object from the mirror is $u = x - 300$.Substituting these into the magnification equation: $x = 3(x - 300)$.$x = 3x - 900$.$2x = 900$.$x = 450 \, cm$.

$A$ candle flame of $3 \, cm$ is placed at $300 \, cm$ from a wall. $A$ concave mirror is kept at distance $x$ from the wall in such a way that the image of the flame on the wall is $9 \, cm$. Then $x$ is......$cm$.

Similar Questions

The distance of a real object from the focus of a convex mirror of radius of curvature $a$ is $b$. Then the distance of the image from the focus is

An object is placed at a distance $u$ from a concave mirror of focal length $f$. $A$ real image is formed on a screen placed at a distance $v$ from the mirror. As $u$ changes,$v$ also changes. Which of the following graphs correctly represents the variation of $1/v$ with $1/u$?

If the distance between an object and its two times magnified virtual image produced by a curved mirror is $15 \,cm$, the focal length of the mirror must be:

The focal length of a concave mirror is $f$ and the distance from the object to the principal focus is $x$. The magnification will be:

All of the following statements are correct except (for a real object):

Vedclass Test Series

Exam Paper Generator

Online Exam Module