A candle placed 25 cm from a lens forms an i | vedclass

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(A) Given: Object distance $u = - 25 \ cm$ (by sign convention,object is placed to the left).Image distance $v = + 75 \ cm$ (image is formed on a scre

Vedclass · Accepted Answer

$+ 18.75 \ cm$ and convex lens

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(A) Given: Object distance $u = - 25 \ cm$ (by sign convention,object is placed to the left).Image distance $v = + 75 \ cm$ (image is formed on a screen on the other side,so it is real).Using the lens formula: $\frac{1}{f} = \frac{1}{v} - \frac{1}{u}$.Substituting the values: $\frac{1}{f} = \frac{1}{75} - \frac{1}{-25} = \frac{1}{75} + \frac{1}{25}$.$\frac{1}{f} = \frac{1 + 3}{75} = \frac{4}{75}$.$f = \frac{75}{4} = + 18.75 \ cm$.Since the focal length is positive,the lens is a convex lens.

$A$ candle placed $25 \ cm$ from a lens forms an image on a screen placed $75 \ cm$ on the other side of the lens. The focal length and type of the lens are:

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