A capacitor of capacitance C is charged with | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The energy stored in a capacitor is given by $U = \frac{1}{2} C V^2$.When the capacitor discharges through the coil,this energy is converted into

Vedclass · Accepted Answer

$500 \,\mu F$

Vedclass · Answer

(B) The energy stored in a capacitor is given by $U = \frac{1}{2} C V^2$.When the capacitor discharges through the coil,this energy is converted into heat,which raises the temperature of the block.The heat gained by the block is given by $Q = m s \Delta T$,where $m$ is the mass,$s$ is the specific heat capacity,and $\Delta T$ is the change in temperature.Equating the energy stored to the heat gained: $\frac{1}{2} C V^2 = m s \Delta T$.Given: $V = 200 \,V$,$m = 0.1 \,kg$,$s = 2.5 	imes 10^2 \,J/(kg \cdot K)$,and $\Delta T = 0.4 \,K$.Substituting the values: $\frac{1}{2} 	imes C 	imes (200)^2 = 0.1 	imes 2.5 	imes 10^2 	imes 0.4$.$\frac{1}{2} 	imes C 	imes 40000 = 10$.$20000 	imes C = 10$.$C = \frac{10}{20000} = \frac{1}{2000} \,F$.$C = 0.0005 \,F = 500 	imes 10^{-6} \,F = 500 \,\mu F$.

Similar Questions

Find $I_1$ and $I_2$ at steady state.

What are the charges stored in the $1 \mu F$ and $2 \mu F$ capacitors in the circuit as shown in the figure once the current $(I)$ becomes steady?

Three identical capacitors are given a charge $Q$ each and they are then allowed to discharge through resistances $R_1, R_2,$ and $R_3$. Their charges,as a function of time,are shown in the graph below. The smallest of the three resistances is

In an $R-C$ charging circuit,the dashed line represents the graph of $\ln I$ versus $t$. If the resistance of the circuit is doubled,which of the following solid lines represents the correct graph of $\ln I$ versus $t$?

$A$ capacitor of capacity $0.1 \mu F$ connected in series to a resistor of $10 M \Omega$ is charged to a certain potential and then made to discharge through the resistor. The time in which the potential will take to fall to half its original value is (Given, $\log _{10} 2=0.3010$ ) (in $\,s$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module