$A$ capacitor with capacitance $5\,\mu F$ is charged to $5\,\mu C.$ If the plates are pulled apart to reduce the capacitance to $2\,\mu F,$ how much work is done?

  • A
    $3.75\times 10^{-6}\,J$
  • B
    $2.55\times 10^{-6}\,J$
  • C
    $6.25\times 10^{-6}\,J$
  • D
    $2.16\times 10^{-6}\,J$

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