A capillary type tube AB is connected to a ma | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The pressure inside the soap bubble at $B$ is given by $P_{in} = P_0 + \frac{4T}{r}$,where $P_0$ is the atmospheric pressure,$T$ is the surface te

Vedclass · Accepted Answer

$\frac{r \rho gh}{4}$

Vedclass · Answer

(D) The pressure inside the soap bubble at $B$ is given by $P_{in} = P_0 + \frac{4T}{r}$,where $P_0$ is the atmospheric pressure,$T$ is the surface tension,and $r$ is the radius of the bubble.The pressure at the same horizontal level in the manometer limbs is equal. Let the pressure at the liquid surface in the open limb be $P_0$. Then the pressure at the level corresponding to the lower limb $D$ is $P_0 + \rho gh$.Equating the pressures at the level of the bubble $B$ and the manometer limb $D$ (assuming $B$ is at the same level as $D$):$P_0 + \frac{4T}{r} = P_0 + \rho gh$Simplifying the equation:$\frac{4T}{r} = \rho gh$Solving for $T$:$T = \frac{r \rho gh}{4}$

Similar Questions

The excess pressure inside a spherical soap bubble of radius $1 \,cm$ is balanced by a column of oil (specific gravity $= 0.8$), $2 \,mm$ high. The surface tension of the bubble is: (in $\,N/m$)

The radii of two soap bubbles are $r_1$ and $r_2$. In isothermal conditions,they meet together in a vacuum. Then the radius of the resultant bubble is given by

What should be the diameter of a soap bubble,in order that the excess pressure inside it is $25.6 \ Nm^{-2}$ (in $cm$)? [surface tension of soap solution $= 3.2 \times 10^{-2} \ Nm^{-1}$]

$A$ number of small water droplets of surface tension '$T$',each of radius '$r$',are combined to form a single drop of radius '$R$'. If the released energy is converted into kinetic energy,then the velocity acquired by the bigger drop is . . . . . . ($\rho$ - density of water)

Vedclass Test Series

Exam Paper Generator

Online Exam Module