A car has to move on a level turn of radius 4 | vedclass

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(B) For a car moving on a level circular road,the centripetal force required for turning is provided by the static friction between the tyres and the

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$30$

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(B) For a car moving on a level circular road,the centripetal force required for turning is provided by the static friction between the tyres and the road.The condition for the car not to skid is that the required centripetal force must be less than or equal to the maximum static frictional force.$F_{c} \leq f_{s,max}$$\frac{mv^{2}}{R} \leq \mu mg$$v^{2} \leq \mu gR$$v_{max} = \sqrt{\mu gR}$Given: $\mu = 0.2,$ $R = 450\,m,$ and taking $g = 10\,m/s^{2}.$$v_{max} = \sqrt{0.2 	imes 10 	imes 450}$$v_{max} = \sqrt{2 	imes 450}$$v_{max} = \sqrt{900}$$v_{max} = 30\,m/s.$

$A$ car has to move on a level turn of radius $450\,m.$ If the coefficient of static friction between the tyre and the road is $\mu = 0.2,$ find the maximum speed the car can take without skidding in $m/s.$

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