A car travels 100, km east and then 100, km s | vedclass

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Question

(D) Average velocity is defined as the total displacement divided by the total time taken.Displacement is a vector quantity representing the shortest

Vedclass · Accepted Answer

$0\, km\, h^{-1}$

Vedclass · Answer

(D) Average velocity is defined as the total displacement divided by the total time taken.Displacement is a vector quantity representing the shortest distance between the initial and final positions.In this problem,the car starts at a point,travels $100\, km$ east,$100\, km$ south,and then returns to the exact same starting point.Since the final position is the same as the initial position,the total displacement is $0\, km$.Therefore,the average velocity = $\frac{	ext{Total Displacement}}{	ext{Total Time}} = \frac{0\, km}{3.3\, h} = 0\, km\, h^{-1}$.

$A$ car travels $100\, km$ east and then $100\, km$ south. Finally,it comes back to the starting point by the south-east route. Throughout the journey the speed is constant at $60\, km\, h^{-1}$. The average velocity for the whole journey if the time taken is $3.3\, h$ is

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