A carbon resistor of (47 pm 4.7) ; kOmega is | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The given resistance is $(47 \pm 4.7) \; k\Omega = 47 	imes 10^3 \; \Omega \pm 10 \%$.According to the carbon resistor color code:$1$. The first

Vedclass · Accepted Answer

Yellow - Violet - Orange - Silver

Vedclass · Answer

(C) The given resistance is $(47 \pm 4.7) \; k\Omega = 47 	imes 10^3 \; \Omega \pm 10 \%$.According to the carbon resistor color code:$1$. The first digit is $4$, which corresponds to the color Yellow.$2$. The second digit is $7$, which corresponds to the color Violet.$3$. The multiplier is $10^3$, which corresponds to the color Orange.$4$. The tolerance is $10 \%$, which corresponds to the color Silver.Therefore, the color code sequence is Yellow - Violet - Orange - Silver.

$A$ carbon resistor of $(47 \pm 4.7) \; k\Omega$ is to be marked with rings of different colours for its identification. The colour code sequence will be:

Similar Questions

Resistance of a carbon resistor determined from colour codes is $(22000 \pm 5 \%) \, \Omega$. The colour of the third band must be:

Which materials are used to prepare wire-bound resistors?

How are carbon film resistors prepared?

In the figure,a carbon resistor has bands of different colours on its body as shown. The value of the resistance is ................. $k\Omega$.

If the last band on the carbon resistor is absent,then the tolerance is (in $\%$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module